Add busy property to ShellApp
Using a separate property to show when the application is busy rather than cramming it into the state property makes the code clearer. In most places we only care if an app is running or not, not whether it is actually busy. https://bugzilla.gnome.org/show_bug.cgi?id=736492
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@ -181,6 +181,7 @@ const AppMenuButton = new Lang.Class({
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this._targetApp = null;
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this._appMenuNotifyId = 0;
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this._actionGroupNotifyId = 0;
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this._busyNotifyId = 0;
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let bin = new St.Bin({ name: 'appMenu' });
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bin.connect('style-changed', Lang.bind(this, this._onStyleChanged));
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@ -457,12 +458,17 @@ const AppMenuButton = new Lang.Class({
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this._targetApp.disconnect(this._actionGroupNotifyId);
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this._actionGroupNotifyId = 0;
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}
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if (this._busyNotifyId) {
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this._targetApp.disconnect(this._busyNotifyId);
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this._busyNotifyId = 0;
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}
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this._targetApp = targetApp;
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if (this._targetApp) {
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this._appMenuNotifyId = this._targetApp.connect('notify::menu', Lang.bind(this, this._sync));
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this._actionGroupNotifyId = this._targetApp.connect('notify::action-group', Lang.bind(this, this._sync));
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this._busyNotifyId = this._targetApp.connect('notify::busy', Lang.bind(this, this._sync));
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this._label.setText(this._targetApp.get_name());
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this.actor.set_accessible_name(this._targetApp.get_name());
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}
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@ -476,7 +482,7 @@ const AppMenuButton = new Lang.Class({
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let isBusy = (this._targetApp != null &&
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(this._targetApp.get_state() == Shell.AppState.STARTING ||
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this._targetApp.get_state() == Shell.AppState.BUSY));
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this._targetApp.get_busy()));
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if (isBusy)
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this.startAnimation();
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else
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