Fix exception when showing menu for not-running app
Need to check windows.length before checking first window. https://bugzilla.gnome.org/show_bug.cgi?id=597466
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@ -440,7 +440,7 @@ AppIconMenu.prototype = {
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// Display the app windows menu items and the separator between windows
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// of the current desktop and other windows.
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let activeWorkspace = global.screen.get_active_workspace();
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let separatorShown = windows[0].get_workspace() != activeWorkspace;
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let separatorShown = windows.length > 0 && windows[0].get_workspace() != activeWorkspace;
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for (let i = 0; i < windows.length; i++) {
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if (!separatorShown && windows[i].get_workspace() != activeWorkspace) {
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