appMenu: Only show 'Quit' for running apps
The top bar menu always corresponds to a running app, so it made sense to include the 'Quit' item unconditionally. That won't be the case for the overview context menus, so handle app state changes and show/hide the item as necessary. Part-of: <https://gitlab.gnome.org/GNOME/gnome-shell/-/merge_requests/1948>
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@ -71,6 +71,7 @@ var AppMenu = class AppMenu extends PopupMenu.PopupMenu {
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this.addMenuItem(new PopupMenu.PopupSeparatorMenuItem());
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this.addMenuItem(new PopupMenu.PopupSeparatorMenuItem());
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this._quitItem =
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this.addAction(_('Quit'), () => this._app.request_quit());
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this.addAction(_('Quit'), () => this._app.request_quit());
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this._signals = [];
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this._signals = [];
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@ -78,10 +79,26 @@ var AppMenu = class AppMenu extends PopupMenu.PopupMenu {
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this._appSystem,
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this._appSystem,
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this._appSystem.connect('installed-changed',
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this._appSystem.connect('installed-changed',
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() => this._updateDetailsVisibility()),
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() => this._updateDetailsVisibility()),
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], [
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this._appSystem,
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this._appSystem.connect('app-state-changed',
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this._onAppStateChanged.bind(this)),
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]);
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]);
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this._updateQuitItem();
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this._updateDetailsVisibility();
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this._updateDetailsVisibility();
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}
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}
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_onAppStateChanged(sys, app) {
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if (this._app !== app)
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return;
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this._updateQuitItem();
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}
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_updateQuitItem() {
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this._quitItem.visible = this._app?.state === Shell.AppState.RUNNING;
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}
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_updateDetailsVisibility() {
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_updateDetailsVisibility() {
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const sw = this._appSystem.lookup_app('org.gnome.Software.desktop');
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const sw = this._appSystem.lookup_app('org.gnome.Software.desktop');
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this._detailsItem.visible = sw !== null;
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this._detailsItem.visible = sw !== null;
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@ -149,6 +166,7 @@ var AppMenu = class AppMenu extends PopupMenu.PopupMenu {
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this._newWindowItem.visible =
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this._newWindowItem.visible =
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app && app.can_open_new_window() && !actions.includes('new-window');
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app && app.can_open_new_window() && !actions.includes('new-window');
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this._updateQuitItem();
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}
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}
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_queueUpdateWindowsSection() {
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_queueUpdateWindowsSection() {
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